How is Smoothing by Bin Medians?
Dear all,
Can anyone shed some light on how Smoothing by Bin Medians is performed?
Thanks.
Regards.
Can anyone shed some light on how Smoothing by Bin Medians is performed?
Thanks.
Regards.
posted by *SIlentISt* | 2/09/2007 01:33:00 PM
2 Comments:
Hi all,
I would like to share my answer for Question 5 “Smoothing by bin means” in our the midterm question.
Step 1:
First of all, the data must be in order(ascending).
Question: smoothing by bin means with a bin depth of 3.
Step 2:
Divide the list of numbers into 3 entries each time into a bin starting from the first number.
26/3= 9 bins, Note: the last bin, you will have only 2 numbers left.
Step 3:
(13,15,16),(16,19,20),(20,21,22),(22,25,25),(25,25,30),(33,33,35),(35,35,35),(36,40,45),(52,70)
Step 4:
Find the mean value for the data in each bin
Mean = sum/number of entries in bin
Step 5:
Bin 1: 13,15,16
Mean = 13+15+16/3 = 14.666, rounded to 15
Bin 2: 16,19,20
Mean = 16+19+20/3 = 18.333, rounded to 18
Bin 3: 20,21,22
Mean = 20+21+22/3 = 21
Bin 4: 22,25,25
Mean = 22+25+25/3 = 24
Bin 5: 25,25,30
Mean = 25+25+30/3 = 26.666, rounded to 27
Bin 6: 33,33,35
Mean = 33+33+35/3 = 33.666, rounded to 34
Bin 7: 35,35,35
Mean = 35+35+35/3 = 35
Bin 8: 36,40,45
Mean = 36+40+45/3 =40.333, rounded to 40
Bin 9: 52,70
Mean = 52+70/2 =61
Step 6:
Just replace all value in each bin with the mean value calculated for each bin in Step 5.
Results after smoothing by means.
Bin 1:{15,15,15}
Bin 2:{18,18,18}
Bin 3:{21,21,21}
Bin 4:{24,24,24}
Bin 5:{27,27,27}
Bin 6:{34,34,34}
Bin 7:{35,35,35}
Bin 8:{40,40,40}
Bin 9:{51,51}
That's all.
Good luck to all of you!
Regards,
Sunthari
Hi all,
Sorry earlier post,message was truncated.
I would like to share my answer for Question 5 “Smoothing by bin means” in our the midterm question.
Step 1:
First of all, the data must be in order(ascending).
Question: smoothing by bin means with a bin depth of 3.
Step 2:
Divide the list of numbers into 3 entries each time into a bin starting from the first number.
26/3= 9 bins, Note: the last bin, you will have only 2 numbers left.
Step 3:
(13,15,16),(16,19,20),(20,21,22),(22,25,25),(25,25,30),
(33,33,35),(35,35,35),(36,40,45),(52,70)
Step 4:
Find the mean value for the data in each bin
Mean = sum/number of entries in bin
Step 5:
Bin 1: 13,15,16
Mean = 13+15+16/3 = 14.666, rounded to 15
Bin 2: 16,19,20
Mean = 16+19+20/3 = 18.333, rounded to 18
Bin 3: 20,21,22
Mean = 20+21+22/3 = 21
Bin 4: 22,25,25
Mean = 22+25+25/3 = 24
Bin 5: 25,25,30
Mean = 25+25+30/3 = 26.666, rounded to 27
Bin 6: 33,33,35
Mean = 33+33+35/3 = 33.666, rounded to 34
Bin 7: 35,35,35
Mean = 35+35+35/3 = 35
Bin 8: 36,40,45
Mean = 36+40+45/3 =40.333, rounded to 40
Bin 9: 52,70
Mean = 52+70/2 =61
Step 6:
Just replace all value in each bin with the mean value calculated for each bin in Step 5.
Results after smoothing by means.
Bin 1:{15,15,15}
Bin 2:{18,18,18}
Bin 3:{21,21,21}
Bin 4:{24,24,24}
Bin 5:{27,27,27}
Bin 6:{34,34,34}
Bin 7:{35,35,35}
Bin 8:{40,40,40}
Bin 9:{51,51}
That's all.
Good luck to all of you!
Regards,
Sunthari
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